look at the figure , the centre of masses of the cylinders form an equilateral triangle force on B due to C F(bc)= mg/2sin30=mg/4 horizontal component of this force= mg/4cos60=mg/8 for 0 net horizontal force mg/8=mgsin@cos@ 1/8=1/2sin2@ sin2@=1/4 @=1/2arcsin(1/4)
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
33
![[Thumb - cylinders.JPG]](/upload/2007/12/2/ddd560a427f8bac29478c12093d5667a_29565.JPG_thumb)
