u reached 2 2 i = f 2 i...fine write it as, e ln2^(2 i) = e lnf^(2 i) this becomes e 2 ln2 i = e 2 lnf i now write it as cos(2  ln2) + isin(2  ln2) = cos(2  lnf) + isin(2  lnf) so u can equate cos(2  ln2)=cos(2  lnf) n sin(2  ln2)=sin(2  lnf) this will have infinite solns but we must take only valid solns cos(2  ln2) = cos(2  lnf +/- 2n  ) ln2=lnf - 1 ln2=ln(f/e) 2=f/e 2e=f
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