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vikalp (148)

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Olaaa!! Perrrfect answer. 24  [38 rates]

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hi ronak ,
as you read this solution make sure that you have HCV in front of you.. i'll be using the same figure ...
the terminology we will be using will be: pulley = 1
                                                          wheel =2          
                    tension in the string between them = T1
                           tension in the string between pulley and mass = T2
now writing the force equations assuming that the mass moves downwards, we have :
for the mass : mg - T2 = ma
for the pulley : T2r1 - T1r1 = I1(1)
for the wheel : T1r2 = I2(2)
also we have : a = r1(1)= r2(2)
 here I = moment of inertia , and r are the radius , a is the acceleration.....
so solving these we get
    T1 = I2(2)/r2 = 6.322 N
[ the expression for T1 = I2mg/{ I2 + mr22 + I1r22/r12 } ]
 

Vikalp Pal .....3rd year Mechanical Eng. IIT Delhi.....
 this reply: 15 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
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