The function would be
f(x) = cosx 2n
<= x <= 2n + /4 sin x 2n +/4 <= x <= (2n+1) +/4 cosx (2n+1) +/4 <= x <= (2n+2)
f '(x) = -sinx 2n <= x <= 2n + /4 cosx 2n +/4 <= x <= (2n+1) +/4 -sinx (2n+1) +/4 <= x <= (2n+2)
Here the critical poins are where the function changes its value and the points where f '(x)=0
Now, for n= -1, u'll get the points
now put n=0, and u'll get
Hence, there are 7 points.
Moderation Team
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