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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Dec 2007 14:49:44 IST
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nik.......the body is not at x=0 at t=0....so displacement is not 81mt.
x=(t+5)2
dx/dt=velocity=2t+10
d2x/dt2=acceleration=2m/s2
so the work done =F.displacement
displa.=81-25=56mt.
so work done= 3.2.56=336Joules.
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"Nenenthedhavano naake teleedu"
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