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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: range 1/2-3Sinx
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priyesh (1612)

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Olaaa!! Perrrfect answer. 260  [416 rates]

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no spidey ur answer is wrong see
f(x) = 1/(2-3Sinx)
when sinx tends to 2/3 from left(i.e just less than 2/3)
f(x) tends to +ve infinity
 
when sinx tends to 2/3 from right (i.e just greater than 2/3)
f(x) tends to -ve infinity
also using boundary condition for sinx when sinx = 1 f(x) = -1 and when sinx = -1 f(x) = 1/5
so it's clear that f(x) can't lie between (-1,1/5) 
 
so range is R - (-1,1/5)  

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 this reply: 7 points  (with Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
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