sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Rotational Mechanics 1
Forum Index -> Community shelf -> View Full Question like the article? email it to a friend.  
Author Message
mukulss (493)

Blazing goIITian

Olaaa!! Perrrfect answer. 75  [134 rates]

mukulss's Avatar

total posts: 601    
offline Offline

Angular Displacement and Velocity

Angular Displacement Illustration When that ball you throw is spinning, it spins with a certain velocity (independent of the velocity of the ball itself as it flies through the air) that is called angular velocity. Like our usual translational velocity, angular velocity is basically the change in angular displacement over the change in time. In the illustration on the right we can see that linear displacement (across the circumference of the circle labeled s) is related to the radius of the circle and angular displacement q. In fact, the linear displacement is merely qr. Please note that q is in units of radians, not degrees (1 radian = 180/p degrees).

Angular velocity is the change in angular displacement over a change in time. Thus angular velocity (w) is defined as follows:
omega = d(theta)/dt


You may notice we use the greek letter w instead of plain old v. This is to distinguish between velocity and angular velocity.

Angular Acceleration

Similar to translational kinematics, angular acceleration (a) is merely the change in angular velocity over the change in time:
alpha = d(omega)/dt


Please note that the linear acceleration used here is the acceleration of a point on the circle parallel, or tangent, to its surface (thus, it is sometimes called tangental acceleration). This is not to be confused with centripetal acceleration, which is the acceleration towards the center of the circle.

To recap:
s = r(theta); v = r(omega); a[parallel] = r(alpha); a[perpendicular] = r(omega^2)


The equation for centripetal equation in terms of angular quantities is the last line written above.

Kinematics Equations, Angular Style

You know what? You can do the exact same derivations we did with translational kinematics to find rotational kinematics equations if we are considering a case with constant angular acceleration. Basically, what comes out is essentially the same equations but with different variables:
Click to view Equation 5-4

this word is so small that it is a foolishness to hate anyone.
so, we love all.
 this article: 16 points  (with Olaaa!! Perrrfect answer.   in 5 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya