NCERT indefinite integral7.6.20
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(x-3)ex/(x-1)3= (x-1-2)ex/(x-1)3= ex((x-1)-2)/(x-1)3hey im not using int sign plz tc of that ex(x-1)/(x-1)3-2ex/(x-1)3 =ex(1/(x-1)2-2/(x-1)3) know take 1/(x-1)2 as a function for which derivative is -2/(x-1)3 so the above int is in the form of ex(f(x)+(f1)) fo r which ans will be in the form of ex(f(x)) therefore ans for above int is ex/(x-1)2 hope its clear if not ask me
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(x-3)ex/(x-1)3=







