Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: NCERT indefinite integral7.6.20
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sowjanya gudipati (73)

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(x-3)ex/(x-1)3=
(x-1-2)ex/(x-1)3=ex((x-1)-2)/(x-1)3
hey im not using int sign plz tc of that
ex(x-1)/(x-1)3-2ex/(x-1)3
=ex(1/(x-1)2-2/(x-1)3)
know take 1/(x-1)2 as a function for which derivative is -2/(x-1)3
so the above int is in the form of ex(f(x)+(f1)) fo r which ans will be in the form of ex(f(x))
therefore ans for above int is ex/(x-1)2
hope its clear
if not ask me
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