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Total (KE+PE) at p = Total (KE+PE) at q (QV + mv2/2)p = (QV + mv2/2)q u (10-8)(600) + (0.001/2)v2 = (0.001/2)(202) v = 280 m/s = 2 70 m/sBest Wishes |
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Bipin Kumar Dubey Chemical Dept. IIT Kharagpur |
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280 m/s = 2







