Before solving let me tell what's wrong with Nishant a) u forgot the clamp exerts some force
now the centre of mass of the entire rod moves in a circle of radius l/2. the only external force is due to the rod . so mw^{2}l/2=F_{clamp} m is the mass of the rod now consider the semi portion of it there are two external forces acting on it one due to clamp and the other due to other half which is say F so considering it's COM which is moving in a circle of l/4 we get F_{clamp}-F=(m/2)w^{2} l/4 so F=mw^{2}l/2 -m w^{2}l/8 so F=3mw^{2}l/8 so stress is F/A=3dw^{2}l^{2}/8 so i ,pannagumaand karthik are right.
Moderation Team
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