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verma-centre of mass
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hey i am using the normal reaction offered by the floor on the chain which is equal to the force exerted by the chain on the floor N=Nwt+Nthrust Nwt=(m/l)xg Nthrust=Vrelative(dm/dt) Vrelative=u-v = v dm/dt=(dm/dy)(dy/dt)=m/l(v) Nthrust=v2(m/l) v=(2gx)1/2 Nthrust=2gx(m/l) N=(m/l)gx+2gx(m/l)=3(m/l)gx
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