i 2 got d same ans but my medhod of solving is different first as given in problem it is continuous at x=1 hence LHL=RHL hence LHL:Lt f(x)= Lt p[1-h+1]+2[1-h-1] x-1- h-0 [x=1-h h>0 a small +ve no] =p-2 n RHL is Lt x-1+ f(x)=Lt h-0 p[1+h+1]+2[1+h+1]=2p hence as said above LHL=RHL hence 2p=p-1 p=-2 rate me if im write plz
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