IIT JEE , AIEEE Forum - Physics , Electricity - the infinite grid again..i dont want the solution as whole..i want to be taught something

bvsatyaram

Well, it's valid doubt. U say when u superimpose, the currents are i,i,i and 2i.
U say the last current is 2i, by adding currents in both cases. But what abt the first thre currents? U r just considering the first case. there will be a significant contribution by the second case, even in the other three branches, of course, we can't find their exact magnitudes.
So, the net currents will be i+i1, i+i2, i+i3 and i+i, where i1, i2 and i3 are currents in 3 branches emerging from A other than AB due to the second case
so, the net current will be 5i+i1+i2+i3. Here u don't know the value of i1, i2 and i3. So, we cant say the answer.. Infact, i1+i2+i3 will turn out to be (-i), making the net current to 4i.

Hope every thing is clear now.

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