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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 12:56:33 IST
Accepted Answer [?]
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while solving this type of probl. u have to find the eqn of line (here chord of contact) first and then eliminate the parameter.
if u get a quadratic in the parameter, equate its discriminant to zero.
here, let point of ellipse be (acosw,bsinw)
eqn of chord of contact on circle is:
axcosw + bysinw = r^2
axcosw + byrt(1-cos^2w) = r^2
now make it a quadratic:
(a^2x^2 + b^2y^2)cos^2w - 2axr^2cosw + (r^4-b^2y^2)=0
equate its discriminant to zero and solve, u'll get
a^2x^2 + b^2y^2 = r^4
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IIT Kharagpur
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