eqn of normal is to ellipse is a^2x/x1 - b^2y/y1 = a^2-b^2 (x1,y1) is the point of intersection of normal n ellipse in this ellipse a=rt(2), b=1 so normal is 2x/x1 - y/y1 = 1 it passes thru (2,3) so 4/x1 - 3/y1 = 1 hence locus of x1,y1 is xy + 3x - 4y = 0
I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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