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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Centre of mass: Verma
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[Post New]14 Dec 2007 00:02:08 IST
    Subject: Re:Centre of mass: Verma
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ramyani (2837)

Blazing goIITian

Olaaa!! Perrrfect answer. 479  [700 rates]
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yes.


( B)

Let v1 be the vel at which the block breaks off.
Then,
intial energy of block = mv2 / 2

kinetic energy of large block  = MV2 / 2

P.E. of small block = mgh

K.E still retained by small block = mv1 2 / 2

ppl. of consv. of energy gives,

mv1 2 / 2   + mgh   =   mv2 / 2 - MV2 / 2

v1 2 / 2   + gh   =   v2 / 2 -  (M / m ) V2 / 2

v1 =  desired result
it is not important where u stand, but in which direction u are moving
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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