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[Post New]10 Dec 2006 21:24:46 IST
    Subject: Re:vaibhav mechanics [Admin]: cartesian equation of trajectory
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cvramana (649)

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Olaaa!! Perrrfect answer. 109  bad job dude!! I dont approve of this answer! 1  [163 rates]
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The magnitude of velocity of projection is given by u = Ö(12 + 22) = Ö5 m/s.  And the angle of projection is given by q where, tan q = 2 /1 = 2.
Therefore 
Y = x tan q - g x2 (1 + tan2 q) / 2 u2.
Y= 2x - 5x2.
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