IIT JEE , AIEEE Forum - Mathematics , Trignometry - given:a+b+c=180;tan{(a+b-c)/4}tan{(b+c-a)/4}tan{(a+c-b)/4}=1RTP-1+cosa+cosb+cosc=

ayshwarya

hey but in exam u wud suffer by doing dees medod ive done in anoder pattern see dis
given tan[pie/4-2c/4]tan[pie/4-2b/4]tanpie/4-2a/4]=1

hence by putting a=0 b=0 c=pie [even pie/2 , pie/2, 0 b chalta]

hence v wud get -1+1-1+1=0 hence proved rate me if u feel good

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