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ritu_007 (603)

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Olaaa!! Perrrfect answer. 113  [132 rates]

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hiiiiii!!!!!
 
1) y=tan2x
 
dy/dx=2 tanx.sec2x
 
2)y=logsinx
 
dy/dx=1/sinx*cosx=cotx
 
3)y=log tanx
 
dy/dx=(1/tanx).sec2x
 
dy/dx=(1/cosx sinx)
 
dy/dx=2/sin2x  (multiply and divide by 2)
 
dy/dx=2cosec2x
 
y=e power tanx
 
but tanx is to the base e.
so y=tanx
 
dy/dx=(1/2^tanx)*sec^2x
 

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