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Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: In how many different ways the no 1440be expressed as product of 2 factors
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harsha_27 (1343)

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Olaaa!! Perrrfect answer. 225  [334 rates]

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the proof comes under number theory ......u just remember the formula given below
if N is any natural no.
and N = [P1^A1][P2^A2][P3^A3].........[Pk^Ak]

then the no. of ways in which N can be resolved into product 2 factors is

         1/2[A1+1][A2+1][A3+1].......[Ak+1]      ,      if N is NOT a perfect square

=

          1/2{ [A1+1][A2+1][A3+1].......[Ak+1] + 1} ,  if N is a perfect square

so for ur qn. the answer if u apply the formula above comes out to be
1/2[5+1][2+1][1+1]=1/2[36] = 18





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