IIT JEE , AIEEE Forum - Physics , Mechanics

Raghudevan

yeah, sorry (t^2) - 40t + 300 = 0

t = [40

^{[2 ]}

1600 - 1200]/2

t = [20

10]

t = 30 sec or 10 sec

we know that the body is under const deceleration of 10cm/sec, so in the first 10 sec itself, the body would have covered 1500cm in the positive direction, then it'll come to a stop, then due to the acc in the -ve direction, it'll start moving in the -ve direction with const acc of 10cm/sec, it takes the body 30sec to cover 1500cm in the -ve direction, first it would have covered 1500cm in the +ve direction, then stopped and then started moving in the -ve direction, it would have covered 1500cm again to reach the mean position and then moved onto 1500cm in the -ve direction, the total time taken for this is 30sec, the net displacement is -1500cm, if we sub, v = 200cm/sec, a = -10cm/sec^2 and t = 30 sec, we get this

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