IIT JEE , AIEEE Forum - Physics , Mechanics - Good Questions from Work Energy Power..Try them

karthik2007

Okay... just follow the soln carefully... better you draw an FBD.

Now, let the body make an angle @ withe the vertical at the instant in breaks off...

So conserving energy, we get:

mgh = 1/2mv² + mgh(1+cos@)/2

Solving for v², we get v² = gh(1-cos@)

Also, balancing forces on the body, we get:

mv²/(h/2) = mgcos@ + N..

now N = 0,

so from this, we get v² = ghcos@/2

Equating the two expressions for v² we get cos@ = 2/3.

So, v = sqrt(gh/3)

But I don't think u need to find vcos@ here... doesn't make sense... did u check the book ans? which book is this from?

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