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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Challenge - rotational mechanics
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rohith291991 (516)

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Olaaa!! Perrrfect answer. 92  [120 rates]

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t=2oR((1+k2)sinA)/5kg(k(1+cosA)+sinA) if both surfaces have fricton otherwise...
t=
2oR(1-kcotA)/5kg

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