Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Permutation
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Priyesh (1601)

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hi
the soln is as following
1.the no. of solns of the word suriti are 6!/2! = 360
2.now let's count the words which wil come before suriti which are words starting with i,r,si,sr,st,sui
3.words starting with i=5!;r=5!/2!;total=60+120=180
4.words starting with si=4!;sr=4!/2!;st=4!/2!;total=24+12+12=48
5.words starting with sui are 3!=6
6.adding all the bold values we get 234
7.now two words are left suriit & suriti but suriit will be placed before suriti there fore suriit will get ranked 235 & suriti 236.
THEREFORE A) IS THE CORRECT ANSWER
 
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