IIT JEE , AIEEE Forum - Chemistry , Organic Chemistry

kbanagar

WELL I REQUEST U TO READ CAREFULLY
CHK THIS OUT
FIRST OF ALL
1.]ALL THE MOLECULES WHICH DONOT CONTAIN THE PLANE OF SYMMETRY SHOW OPTICAL ISOMERISM.THESE MOLECULES HAVE NONSUPERIMPOSABLE MIRROR IMAGES

NOTE
THIS THING IS SURE THAT MOLECULES CONTAINING THE PLANE OF SYMMETRY IS NOT OPTICALLY ACTIVE.
SO PLANE OF SYMMETRY SHOULD NOT BE THERE
so itz a mandatory condition

secondly,
as others comment on the fact that chirality decides the optical activity or not
lookin the defn " a chiral molecule is one which is connected to diff groups "wat does this mean that there is no plane of symmetry
THIS MEANS THE FIRST CONDITION IS SATISFIED
BUT AGAIN CHIRALITY CANNOT ALONE DECIDE THE CONDITION

TAKING THE EXAMPLE OF MESO TARTARIC ACID

MESO TARTARIC ACID

                                      COOH
                                       I
                                   H-C-OH     {PLANE OF SYMETRY}
                  - ------------------ I---------------------------
                                  H- C-OH
                                       I
                                       COOH

IT CONTAINS SYMMETRY PLANE AS MENTIONED EARLIER ITZ NOT OPTICALLY ACTIVE

WELL AS BALGANESH{MORRISON} SAID
HIS IS ALSO CORRECT
*BUT WAT ABT THIS ONE.

DO RATE ME IF I'M CORRECT.

Ask & Discuss Questions with Community & Experts