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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jan 2008 14:44:39 IST
Accepted Answer [?]
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The min no of tosses required for B to go bankrupt is 21.
There is no max no of tosses, as the game can go for ever.
The next min no of tosses is 23. Then 25, 27, 29... so on.....
Find probability for the occurence of each of these cases. and also find probability for B to loose in each of theses cases. Multiply these two probabilities in each case....
Now u will get an infinite series (coresponding to 21,23,25,27,29,......)
Add this series to get answer.
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Satyaram B V,
General Secretary, Mandakini Hostel,
IIT Madras |
this reply: 5 points
(with 1 
in 1 votes ) [?]
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