IIT JEE , AIEEE Forum - Physics , Electricity

feynmann

We know that potential due to a single wire = @ / 2 pi

o ln ( r ) + const

So we have potential at ( x, y , z ) V =

1 / 4pi

{ @ 1 ln ( y^ 2 + z^2 ) + @ 2 ln ( z^2 + x^2 ) + @3 ln ( x^2 + y^2 ) } + const

where @ s are corresponding linear charge density of x , y , z axes respectively .

Now calculate the potential diff . ( const term cancels out )

ans is 5@ /(4 pi

o) ln ( 1/2 )