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See the electric field at a distance r from the origin is given by E = K Q / r^2 Now energy density U = 1/2  o E^2 So the total energy is  U* 4 pi r^2 dr ( from  to 3a ) + U *4 pi r^2 dr ( from a to 2a ) Carrying out this integral and noting that 4 pi o = 1/K , we get total energy = 5 / 12 K Q ^2 /a We are breaking the limit in this fashion because we know that E inside any conducting shell = 0 in the electrostatic case .
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Moderation Team
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