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konichiwa2x (2234)

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Olaaa!! Perrrfect answer. 420  [487 rates]

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60cm
80cm

For standing waves to be produced, the length of the string between one end to the joint must be an integral multiple of . The frequency of the wave produced in each wire should be the same.

Therefore,


The mass per unit length of the wire = density of the wire x area of cross section.
Make sure you convert all the quantities into the same units.
You'll see that

So,  

        

 
Take

Hence, required frequency is =
Plug in the values and you get , frequency = 179.025 hz

Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm

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