STRUCTURE OF ETHYNE{C2H2} SP-HYBRIDISATION ONE MOLECULE OF ETHYNE HAS 2 CARBON ATOMS AND 2 HYDROGEN ATOMS THE GR &EXITED STATE OF CARBON ARE GIVEN BELOW ground state:1s2 2s2 2p1x2p1y exited state: 1s2 2s12p1x 2p1y 2p1z
one 2s &one 2px orbital of each carbon atom undergo sp hybridisation to give 2 identical sp-hybrid orbitals. these r oriented at an angle 1800 .
one hybrid orbital of each atom overlaps wit the other to form 1 c-c sigma bond . the other hybrid orbital of each carbon atom overlaps with 1s atomic orbitals of hydrogen to form 2 carbon hydrogen sigma bonds. the unhybridised 2py orbital s of both the carbon atom s over lap side ways to form 1 carbon carbon pie bond . similarly the 2pz orbitals of both the carbon atoms overlap on sideways to form another carbon carbon pie bond .
COMPOSITION OF ETHYNE MOLECULE: Ethyne molecule consists of two C-atoms and two H-atoms (C2H2). NATURE OF HYBRIDIZATION: In ethyne molecule, each carbon atom is Sp-hybridized. Due to Sp-hybridization each carbon atom generates two Sp-hybrid orbitals. In this way there exists four Sp-orbital in ethyne. These Sp-orbital are arranged in linear geometry and 180o apart. Remaining py and pz unhybrid orbitals of each carbon atom lie perpendicular to the plane of Sp-orbitals. SIGMA BOND FORMATION: One Sp-hybrid orbital of each carbon atom overlaps to produce one sigma bond between two C-atoms.The remaining one Sp-orbital of each C-atom overlaps with one H-atom to produce sigma bond. Pi-BOND FORMATION: Py and Pz orbital of two carbon atoms are un-hybrid and make parallel overlapping to produce pi-bond. BOND LENGTH: The C--H bond is 1.09A and C-C is 1.2A.o. BOND ANGLE: HCC bond angle is 180o.