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y=ax
x+y=a
solving
x+ax=a
x(1+a)=a
x=a/(1+a)
therefore y=a^2/(1+a)
thus pt of intersection is (a/(1+a),a^2/(1+a))
the line y=ax cuts the origin thus another vertex in the triangle is(0,0)
the line x+y=a cuts the y axis at x=0 implies the point (0,a)
using the area of triaangle formula in co ordinate geometrey solve
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Moderation Team
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