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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Jan 2008 20:13:22 IST
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sin(y-x)=5/13 => cos(y-x) = 12/13 => tan(y-x) = 5/12
cos(y+x)=4/5 => sin(y+x) = 3/5 => tan(y+x) = 3/4
tan 2y = tan ((x+y) + (y-x)) = (tan(x+y) + tan(y-x))/(1 - tan(x+y)*tan(y-x))
= (3/4 + 5/12)/(1 - (3/4) * (5/12))
= (14/12)/(11/16) = 56/33
(sorry for mis-calculations if any , as ans is not matching with previous ones)
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Sprinkle |
this reply: 15 points
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