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@siddartha100
I had typed an almost similar answer completely but after it was pointed out that n= 28 is also an option , I deleted it. there is some fault in our reasoning.
If we check the case when n=28, we can see that it is not necessary that k or k+1 is divisible by n. It is possible that n= pq where p and q are 2 integers and
k=3p2 and k+1 = q2 ,etc .
Now I don't think that we can exhaustively find all the possible values for n , we will have to find a theoratical answer.
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Moderation Team
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