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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jan 2008 19:52:09 IST
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a short cut 4 dis is 1st as it is mentioned ven |z| =1 lets take z=i
hence p(z)=c-1+ib hence |p(z)| =1
so b^2 +c^2 -2c =0 hence b^2+c(c-2) =0
since b^2 is non -ve so b=0 c=0 c=2 r d so.lution der
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