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This can be done by double integration f(x)= 0 infinity e -x2dx multiply both side by 0 infinity ae -a2da 0 infinity e -a2 ada f(x) = 0 infinity0 infinity (ae -x2-a2da)dx put x2+a2=t 2ada=dt,ada=1/2dt put in this integration = 0 infinity 0 infinity((1/2e -t)dt)dx =-1/2 0 infinitye -tdx =-1/2 0 infinitye -(x2+a2)dx= put x2+a2=t 2xdx=dt solve this i think the ans should be = pi/  2
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Moderation Team
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