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[Post New]24 Jan 2008 20:42:12 IST
    Subject: Re:a particle moves along
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akhil_o (2709)

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Olaaa!! Perrrfect answer. 435  [702 rates]
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a=-kx
 
v dv/dx=kx
v dv= kx dx
integratin both sides
v2  x2
 
hence loss in KE is proportional to x square
option b
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