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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jan 2008 22:35:49 IST
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lim(x-0) [1/x-1/sinx]
=(sinx-x)/xsinx
consider sinx-x/x cubed
by applying l'hospital's rule we get value to b -1/6(when x tends to 0)
so given = (sinx-x)/x cubed * x square /sinx
so answer is 0
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