Hey,

the first one i am unable to proceed....since the function

x²f(x)-2f(1/x)=g(x)

Putting -x

(-x)²f(-x)-2f(-1/x)=g(-x)...

now since f(x)-->even

               g(x)-->odd           f(x)=f(-x); g(x)=-g(-x)

therefore

ON ADDING

2x²f(x)-4f(1/x)=0

f(x)=[2/x²] f(1/x)

ON SUBTRACTING

2g(x)=0 or g(x)=0

--> g(x)=0

Now,

        x=5

             25f(5)-25f(5)/2=0 or

            f(5)=0

 

Please......there might be errors...please do mention.moreover its afternoon ....