xy2=1-x
y^2=-1+ 1/x ------(1)
we can make the foll obs about the curve
1.it is symm abt the x-axis
2. for y=0,
1/x -1=0
or x=1
i.e, the curve cuts the x axis at (1,0)
3.LHS is always positive
(1/x -1) >= 0
or x<= 1, i.e, the curve exists for x<1
4.the curve doesnot exist for x<0
5.thrfore domain of f(x) is 0<x<1
6. as x----> 0, y------>
Moderation Team
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