1. A body is dropped from height 'h'. At the same time, another body is projected upwards vertically with a velocity 'u'.
***They will meet after a time : ( h / u )
***Their meeting is at a distance of : gh2 / 2u2
2. 'n' balls, thrown every second such that one ball thrown when the previous one reaches its maximum height. This maximum height = g / 2n2
3. Consider : Ball thrown vertically upwards passes through the same point during times, t1 and t2
(a) t1 + t2 = 2u / g = 2t ( 't' - time taken to reach the maximum height from the ground)
(b) t2 = t1t2
4. Body is dropped from a height. Time taken to cover successive unit distances are in the ratio :
1 : 2 - 1 : 3 - 2 : 4 - 3 : ...................
5. A body is dropped from the top of a tower and after 'n' seconds, another body is thrown downwards with a velocity ' v '. They may meet after a time :
t = ( { gn / 2 } - v ) / ( gn - v )
6. Body 1 accelerates from rest at a constant rate 'a'. Body 2, at a distance of 'd' from Body 1 ( Body 2 is at the back of the Body 1 ) should have a minimum velocity ' v ' to meet the Body 2 where : v = 2ad