|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jan 2008 12:12:15 IST
|
|
|
in first rxn.... OH- acts as a nucleophile and thus nucleophillic substitution takes place to give alcohol...
but in case of alcoholic KOH...u have to visualise it as R'O-...(supposing alcohol is R'OH...then KOH and ROH react to give R'O- K+) ...
R'O- in this rxn acts as a base and eliminates HX frm the halide....
in this rxn, ether is also formed....
i think u have not studied its mechanism....when u'll study it u'll be more clear...
|
this reply: 7 points
(with 1 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
