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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Random Probability
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akhil_o (2704)

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Olaaa!! Perrrfect answer. 434  [701 rates]

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total posts: 1451    
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total answers are 6
there is 1 perfect solution, lets say 3 marks(1 mk each) with probability= 1/6
2 answers with no correct annswer (0 mks) with prob=2/6=1/3
3 answers with just 1 correcrt answer( 1 mk) wit hprob= 3/6 =1/2
 
hence required avg
= 3(1/6)+(0)1/3+(1/2)1
=1/2+1/2
=1
hope it was helpful
 
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