sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: spring constant
Forum Index -> Mechanics -> View Full Question like the article? email it to a friend.  
Author Message
apoorva_43 (223)

Hot goIITian

Olaaa!! Perrrfect answer. 39  [53 rates]

apoorva_43's Avatar

total posts: 187    
offline Offline
say we got 2 springs
if x1 n x2 r displacements of springs
then x1= -F/K1 n x2= -F/K2
x1+x2= -F(1/K1+1/K2)
n so xeq= -F/Keq
-F/Keq=-F(1/K1+1/K2)
so 1/Keq=1/K1 +1/K2

<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
 this reply: 12 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya