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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: random probability
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ayshwarya (280)

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Olaaa!! Perrrfect answer. 52  [62 rates]

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her P(x=r) = nCr p^(n-r) [1-p]^r even 4 P(x=n-r) hence by solving v wud get

[ p/(1-p)] ^n-2r =given hence as it was said dis is independent so p/(1-p) must b equal 2 1 [1 is indepemdent of any power] hence p=1-p so p=1/2

bolo bharat maata ki jai







 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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