from the figure we see that

the direction of normal force of small sphere against the horizontal is given by

mg tan A

from the triangle,

we see that tan A=24/18=4/3

weight of small sphere is 15kg=15*10

=150

Hence force in horizontal direction=150*4/3

=200 N

Hence force at R is 200 N

 

Now weight of the bodies is the only downward acting force

So to balance weight at Q we have to balance both weights

ie (60+15)10

=750 N

Hence the answer is option d

 

Rate if correct

nudhe if doubtful