IIT JEE , AIEEE Forum - Mathematics , Algebra

sboosy

actually there is no restriction on the number of digits
reason:
divisibility by 11 :abcde(a,b,c,d,e are digits)
condition is (a+c+e)-(b+d)=11k where k is whole number
that is it can be equal to 0 or 11 or 22 etc
now consider palindromes
2 digit number (11 itself obviously is divisible)
3 digits 121
4 digits 1001
5 digits 11011
....
so it is so easy to generate a palindrome divisible by 11
technique is
even no of digits means put 1st and last digit as 1 rest as 0
odd no of digits means 1st 2 digits and last 2 digits as 1 and rest as 0
this ofcourse can include few of the possible palindromes
rest can be derived similarly
so there is no restriction on the no of digits

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