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lets , start from the equations----
when the partical is coming down,
v=gt ---------------1
due to elasticcollision ,its velocity changes from +ve to -ve,but ,k.e not changes , before & after collision,means the magnitude of velocity remains unchanged even after collision....
kinetic energy=1/2(mv^2)=1/2m(gt)^2.
now as, we know , m & g are the constants, we take 1/2mg^2=x;
then kinetic energy = xt^2.
therefore,,
K.E.=xt^2
IT IS A UPWARD PARABOLA,which is like, y=kx^2 curve.
the max. k.e.(1/2m(gt)^2) . (corresponding to t=(2h/g)^1/2 and symmetrically ,it goes down then after ,to attend value of k.e=0.
please ,think about it carefully, you 'll surely benefit from this....
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