|
|
the reflected wave travels( 5+5) m while the other wave travels only 6m. since the waves are in phase when they are emitted from the source, the extra distance they travel will create a phase diff b/w the waves.
path diff = 10-6 = 4.
then path diff/Wavelenght = Phase diff/2*pi
for const inteference phase diff = 2*n*pi,
therefore path diff/ n = Wavelenght,
for max wavelenght , n=1
|
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
3
