IIT JEE , AIEEE Forum - Chemistry , Organic Chemistry

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The answer is A.

Br2 is a mild oxidising agent and since Glucose has a free aldehyde group oxidation of the aldehyde group takes place.(note:aldehydes can be oxidised into carboxylic acids even by mild oxidising agents.)

Br₂ + 2 e^-à 2Br^-

The first carbon will become -COOH . The sixth carbon is -^CH₂^OH

and it cannot be oxidised by Bromine water.

So it remains as

^CH₂^{OH .}

^{All the other carbons are unaffected by bromine water.So it retains the configuration as such.}

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