Q2 Let s-a=m and s-b=n and s-c=p
and as 2s=a+b+c
then solve
it becomes
= I (p+n)
2 m
2 m
2 I
I n2 (p+m)2 n2 I
I p2 p2 (m+n)2I
apply C1 tends to C1- C2 and C2 tends to C2 - C3
then take out (m+n+p) common from C1 and C2.
= (m+n+p)2 I n+p-m 0 m2 I
I n-p-m p+m-n n2 I
I 0 p-m-n (m+n)2I
apply R3 tends to R3 -(R1+R2)
Then take 2 common from R3
after that
apply
R1 tends to R1 -( m/n)R3
R2 tends to R2 -(n/m)R3
expand along C3
then apply
C1 tends to C1 + C2
u get ur answer as
= 2mnp(m+n+p)^3
substitute values of m,n,p
Moderation Team
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